Xe would certainly be your central atom, O is attached come it through a doublebond and also your two Fs room attached it is in a single bond.
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There would be 3 Lone Pair (LP) electrons around F, 2 approximately O,and 2 about Xe. Why ? there is no valance to this molecule so youwant to fulfill the formal fee to be 0. Formal fee =(#electrons in floor state) - < (free electrons) - 1/2 (bondingelectrons)>.
Formal charge for F, would want 0 so
0 = 7 - + 1/2 (2) > = 7 - (? +1) = 7 - ? - 1
? = 6, thus 3 lone pairs approximately fluorines.
Formal fee for O, would want 0 so
0 = 6 - + 1/2 (4) >...
? = 4, as such 2 LP about oxygen
Formal charge for Xe, again we desire it to be 0 so,
0 = 8 - + 1/2 (8)>.....
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? = 4, because of this 2 LP roughly Xe.
Kind that a weird collection up (since Xe does no follow the octectrule), however it works out =)
Wiki User∙ 9y ago
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