We’re being asked to recognize the mole portion of glucose (C6H12O6) in a 1.86 M aqueous glucose solution.
You are watching: What is the mole fraction of solute in a 3.19 m aqueous solution?
Aqueous way that water is the solvent. Hence, glucose is the solute.
Mole fraction (X)relates the moles of solute and also solvent within a solution:
mole fraction (X)=mole of solutemole of solution
We’ll calculation the mole portion of glucose utilizing the following steps:
Step 1: Determine the mole of solute using the molarity that the solution.Step 2: calculate the fixed of the solvent using the molarity and density of the solution.Step 3: calculate the mole of the solvent.Step 4: Calculate the mole fraction.
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Determine the mole portion of glucose, C6H12O6, (molecular weight 180.18) in a 1.86 M aqueous glucose solution offered the thickness of the glucose solution is 1.38 g/cm3.
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Our tutors rated the an obstacle ofDetermine the mole fraction of glucose, C6H12O6, (molecular ...as medium difficulty.
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Based on ours data, we think this difficulty is appropriate for Professor Sotero's class at UCF.
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